2
2 C–
-Normality and C-
-Normality
Recall that a topological space
is called an
-normal space (Arhangel’skii and Ludwig, 2001) if for every-two disjoint closed subsets
and
of
there are two open subsets
and
of
such that
is dense in
;
is dense in
, and
, and a topological space
is called a
-normal space (Arhangel’skii and Ludwig, 2001) if for every-two disjoint closed subsets
and
of
there are two open subsets
and
of
such that
is dense in
;
is dense in
, and
. A topological space
is called C-normal (AlZahrani and Kalantan, 2017) if there exist a bijective function
from
onto a normal space
such that the restriction map
from
onto
is a homeomorphism for any compact subspace
of
.
Definition 1.1
A topological space
is called C-
-normal (C-
-normal) if there exist a bijective function
from
onto
-normal (
-normal) space
such that the restriction map
from
onto
is a homeomorphism for any compact subspace
of
.
In these definition, we call the space
a witness of C-
-normal (C-
-normal) and the function
is called a witness function.
A topological space
is called
-regular (Alzahrani, 2022) if for any
and a closed subset
such that
there are two disjoint open sets
;
such that
and
. And topological space
is called almost
-regular (Alzahrani, 2022) if for any
and a regular closed subset
such that
there are two disjoint open sets
;
such that
and
.
Lemma 1.2
Any regular space is
-regular.
Proof
Let
be a regular space. Pick
and
be a closed set such that
, then there exist two disjoint open sets
and
subsets of
where
and
, hence
(note that
since
is closed), and
, therefore
is
-regular space.
Lemma 1.3
(Alzahrani, 2022) Any
-regular space is almost
-regular.
From Lemma 1.2. and Lemma 1.3. we conclude the following corollary.
Corollary 1.4
Any regular space is almost
-regular.
Lemma 1.5
Any normal space is
-normal.
Lemma 1.6
Any normal space is
-normal.
Proof
Let
be a normal space. Pick two disjoint closed sets
and
subsets of
. Since
is normal, then there exist two disjoint open sets
and
subsets of
where
,
and
. Hence
and
. It remains to prove
. For a normal space Y, if F is a closed set, U is an open set and F ⊆ U, then there exist an open set V such that F ⊆ V ⊆
⊆ U. Now apply this to
and set
= V and
= Y\
.
So we have the following theorem.
Theorem 1.7
Any C-normal space is C-
-normal (C-
-normal).
The converse is true under some conditions, first we mention some definition.
A Hausdorff space
is extremally disconnected (Engelking, 1977) if the closure of any open set in
is open. A topological space is called mildly normal (Shchepin, 1972) if any two disjoint regular closed subsets can be separated.
Theorem 1.8
Any
-normal extremally disconnected space is normal.
Proof
Let
be a
-normal extremally disconnected space. Pick two disjoint closed sets
and
subsets of
. Since
is
-normal, then there exist two disjoint open sets
and
subsets of
where
and
. Hence
and
. However,
∩
= ∅ since
is open and
∩
= ∅. Thus,
∩
= ∅ as well since
is open (by extremally disconnectedness) and
∩
= ∅.
Therefore
is normal space.
From Theorem 1.8, we have the following.
Theorem 1.9
If
is
-
-normal (
-
-normal) such that the witness of
-
-normal (
-
-normal) is extremally disconnected, then
is
-normal.
Theorem 1.10
If
is
-
-normal such that the witness of
-
-normal is mildly normal, then
is
-normal.
Proof
Let
be C-
-normal. Then the codomain
witness of C-
-normal is
-normal. Let
and
be any disjoint closed subsets of
. Since
is
-normal, there exist open subsets
and
of
where
,
and
. So
,
are disjoint regular closed subsets containing
and
respectively. Since
is mildly normal, there exist disjoint open subsets
and
of
where
and
. Hence
is normal.
Lemma 1.11
Any
-normal space satisfying
axiom is Hausdorff.
Proof
Let
be any
-normal
-space. Let
be any two distinct elements in
. Hence
and
are disjoint closed subsets of
, by
-normality, there exist two disjoint open subsets
and
of
where
and
which implies
and
. Therefore
is Hausdorff.
Lemma 1.12
Any
-normal space satisfying
axiom is regular (hence Hausdorff).
By Corollary 1.4. we have the following result.
Corollary 1.13
Any
-normal space satisfying
axiom is almost
-regular.
Also by Lemma 1.12 and Lemma 1.2 we have the following result.
Lemma 1.14
Any
-normal space satisfying
axiom is
-regular.
Corollary 1.15
Any
-normal space satisfying
axiom is
-regular.
By Lemma 1.3. we conclude the following corollary.
Corollary 1.16
Any
-normal space satisfying
axiom is almost
-regular.
Proposition 1.17
(Murtinov́a, 2002) Every first countable
-normal Hausdorff space is regular.
Recall that a topological space (Y, τ) is called submetrizable (AlZahrani and Kalantan, 2017) if there exists a metric d on Y such that the topology τ d on Y generated by d is coarser than τ.
Theorem 1.18
Every submetrizable space is C-
-normal (C-
-normal).
Proof
Let
be a submetrizable space, the there exists a metrizable
such that
. Hence
is
-normal since it is normal, and the identity function
from
onto
is a one-to-one and continuous function. If we take
any compact subspace of
, then
is hausdorff, since it is subspace of
, and by (Engelking, 1977);3.1.13];
is a homeomorphism.
Example 1.19
The Rational Sequence Topology
(Steen and Seebach, 1995) is submetrizable being finer than the usual topology
, so
is C-
-normal (C-
-normal).
The converse of Theorem 1.18. is not true in general, for example
is C-
-normal (C-
-normal) which is not submetrizable.
Apparently, any
-normal (
-normal) space is C-
-normal (C-
-normal), to prove this, just by considering
and
is the identity function.
While in general the converse is not true. We provide some examples below.
Example 1.20
-
The Half-Disc topological space (Steen and Seebach, 1995) is C-
-normal (C-
-normal) because it is submetrizable by Theorem 1.18. but it is not
-normal nor
-normal because it is first countable and Hausdorff but not regular, so by Proposition 1.17. the Half-Disc topological space is not
-normal space, hence not
-normal. In general C-
-normality (C-
-normality) do not imply
-normality (
-normality) even with Hausdorff or first countable properties.
-
The Deleted Tychonoff Plank (Steen and Seebach, 1995), it is C-
-normal (C-
-normal) since it is locally compact by Theorem 2.7. but it is not
-normal nor
-normal see (Arhangel’skii and Ludwig, 2001).
-
The Dieudonn
Plank (AlZahrani and Kalantan, 2017), in example 1.10 we proved that it is C-normal, hence it is C-
-normal (C-
-normal) by Theorem 1.9. but it is not
-normal nor
-normal see (Arhangel’skii and Ludwig, 2001), also not locally compact, hence this example also shows that the converse of Theorem 2.7. is not true.
-
The Sorgenfrey line square
see (Steen and Seebach, 1995) is not normal, but it is submetrizable space being it is finer than the usual topology on
, so by Theorem 1.18. it is C-
-normal (C-
-normal).
Theorem 1.21
If
is a compact non–
-normal (non–
-normal) space, then
can not be C-
-normal (C-
-normal).
Proof
Assume
is a compact non–
-normal (non–
-normal) space. Suppose
is C-
-normal (C-
-normal), then there exists
-normal (
-normal) space
and a bijective function
where the restriction map
from
onto
is a homeomorphism for any compact subspace
of
. As
is compact, then
, and we have a contradiction as
is
-normal (
-normal) while
is not. Hence
can not be C-
-normal (C-
-normal).
Observe that a function
witnessing of C-
-normal (
-
-normal) of
not necessarily to be continuous in general, and here is an example.
Example 1.22
Let
with the countable complement topology
(Steen and Seebach, 1995). We know
is
and the only compact sets are finite, hence the compact subspaces are discrete. If we let
be the discrete topology on
, then obviously the identity function from
onto
is a witnessing of the C-
-normality (C-
-normality) which is not continuous.
But it will be continuous under some conditions as the following theorems.
Theorem 1.23
If
is a C-
-normal (C-
-normal) and Fréchet space, then any function witnessing of C-
-normality (C-
-normality) is continuous.
Proof
Let
be a Fréchet C-
-normal (C-
-normal) space and
be a witness of the C-
-normality (C-
-normality) of
. Let
and pick
. There is a unique
where
thus
. since
is Fréchet, then there exists a sequence
where
. As the subspace
of
is compact, the induced map
is a homeomorphism. Let
be any open neighborhood of
. Then
is an open neighborhood of
in the subspace
. Since
is a homeomorphism, then
is an open neighborhood of y in K, then there exists
where
hence
then
Hence
and
Thus
is continuous.
Since any first countable space is Fréchet, we conclude that, In C-
-normality (C-
-normality) first countable space a function
is a witness of the C-
-normality (C-
-normality) of
is continuous. Also, by theorem (Engelking, 1977),3.3.21], we conclude the following.
Corollary 1.24
If
is a C-
-normal (C-
-normal)
-space and
is a witness function of the C-
-normality (C-
-normality), then
is continuous.
For simplicity, let us call a
space which satisfies that the only compact subspaces are the finite subsets F-compact. Clearly F-compactness is a topological property.
Theorem 1.25
If
is F-compact, then
is
-
-normal (
-
-normal).
Proof
Let
be a F-compact. Let
and let
with the discrete topology. Hence the identity function from
onto
does the job.
Example 1.26
Consider
, where
is the countable complement topology (Steen and Seebach, 1995). We know
is
and the only compact sets are finite, therefore, by Theorem 1.25.
is
-
-normal (
-
-normal). This a fourth example of
-
-normal (
-
-normal) but not
-normal (nor
-normal).
Notice that any topology finer than a
topological space is
. Also any compact sub set of a topological space
is compact in any topology coarser than
on
.
Hence any topology finer than F-compact topological space is also F-compact. As an example,
denotes the Fortissimo topology on
, see [14, Example 25]. We know that
is finer than
which is F-compact, hence
F-compact too. Thus,
is
-
-normal (
-
-normal).
Theorem 1.27
C-
-normality (C-
-normality) is a topological property.
Proof
Let
be a C-
-normal (C-
-normal) space and let
. Let
be a
-normal (
-normal) space and let
be a bijective function where the restriction map
from
onto
is a homeomorphism for any compact subspace
. Let
be a homeomorphism. Hence
and
satisfy the requirements.
3
3 C–
-Normality (C-
-Normality) and some other properties
Definition 2.1
A topological space
is called C-
-regular if there exists a bijective function
from
onto
-regular space
such that the restriction map
from
onto
is a homeomorphism for any compact subspace
of
.
This definition is new and we will study some of its properties later.
Corollary 2.2
If
is C-
-normal (C-
-normal) space and the witness of the C-
-normality (C-
-normality) of
is
, then
is C-
-regular.
We prove this corollary by Lemma 1.11, Lemma 1.12. We defined C-regular in (AlZahrani, 2018).
Corollary 2.3
If
is C-
-normal space and the codomain witness of the C-
-normality of
is
, then
is C-regular.
We prove this corollary by Lemma 1.12.
Corollary 2.4
If
is a C-
-normal (C-
-normal) Fréchet space and the witness of the C-
-normality (C-
-normality) is
, then
is
.
Proof
Let
is a C-
-normal (C-
-normal) Fréchet space, then there exist
-normal (
-normal) space
(witness of the C-
-normality (C-
-normality)) and a bijective function
such that the restriction map
from
onto
is a homeomorphism for any compact subspace
of
, then by Theorem 1.23.
is continuous. Let any
be such that
, then
,
. Since
is
-normal (
-normal) and
, then by Lemma 1.11 (Lemma 1.12) the space
is
, then there exist
and
are open sets in
where
and
. Since
are open sets in
and
is continuous, then
and
are open sets in
,
and
. Hence
is
.
Theorem 2.5
Any C-regular Fréchet Lindelof space is C-
-normal (C-
-normal).
Proof
Let
be any C-regular Fréchet Lindelof space. Let
be a regular space and
be a continuous bijective function see Theorem 1.23. By (Engelking, 1977); 3.8.7]
is Lindelof. Since any regular Lindelof space is normal (Engelking, 1977), 3.8.2]. Hence
is C-
-normal (C-
-normal).
C-
-normality (C-
-normality) does not imply C-
-regularity nor C-regular, for example.
Example 2.6
Consider the real numbers set
with its right ray topology
, where
. As any two non-empty closed sets must be intersect in
, then it is normal, and by Lemma in above, it is
-normal (
-normal), hence C-
-normal (C-
-normal). Now, suppose that
is C-
-regular. Take
-regular space
and a bijective function
from
onto
where the restriction map
from
onto
is a homeomorphism for any compact subspace
of
. We know that a subspace
of
is compact if and only if
has a minimal element. Hence
is compact, then
is a homeomorphism, it means
as a subspace of
is
-regular which is a contradiction, since
is closed in subspace
and
, but any non-empty open sets on
must intersect. Then
cannot be C-
-regular (C-regular).
Recall that a topological space
is called Locally Compact (AlZahrani and Kalantan, 2017) if
is Hausdorff and for every
and every open neighborhood
of
there exists an open neighborhood
of
such that
and
is compact.
Theorem 2.7
Every locally compact space is C-
-normal (C-
-normal).
Proof
Let
be locally compact space. By (Engelking, 1977), 3.3.D], there exists
compact space
and hence
-normal (
-normal), and a continuous bijective function
. We have
from
onto
is a homeomorphism for any compact subspace
of
, because continuity ,1–1 and onto are inherited by g, also
is closed since
is compact and g(K) is
.
Example 2.8
Consider
, the first uncountable ordinal, we consider
as an open subspace of its successor
, which is compact and hence is locally compact [14, Example 43]. Thus,
is locally compact as an open subspace of a locally compact space, see (Engelking, 1977),3.3.8]. Then by Theorem 2.7.
is C-
-normal (C-
-normal).
The converse of Theorem 2.7. is not true in general. We introduce the following example of C-
-normal (C-
-normal) which is not locally compact.
Example 2.9
Consider the quotient space
. Let
, where
. Define
as follows:
Now consider
with the usual topology
. Define the topology
on
. Then
is a closed quotient mapping. We explain the open neighborhoods of any element in
as follows: The open neighborhoods of each
are
where
is a natural number. The open neighborhoods of
are
, where
is an open set in
such that
. It is clear that
is
, but it is not locally compact .
is a continuous image of
with its usual topology, so it is Lindelof and
, then
is
. Hence it is C-
-normal (C-
-normal).
A topological space
is called Epi-
-normal (Gheith and AlZahrani, 2021) if there is a coarse topology
on
such that
is
-normal and
. A topological space
is called Epi-
-normal (Gheith and AlZahrani, 2021) if there is a coarse topology
on
such that
is
-normal and
. We defined Epinormal in (AlZahrani and Kalantan, 2016). By the same argument of Theorem 1.18. we can prove the following corollary.
Corollary 2.10
Every epinormal space is C-
-normal (C-
-normal).
Corollary 2.11
Every epi-
-normal (epi-
-normal)space is C-
-normal(C-
-normal).
Any indiscrete space which has more than one point is an example of a C-
-normal (C-
-normal) space which is not epi-
-normal (epi-
-normal).
The converse of Corollary 2.9 is true with Fréchet property.
Theorem 2.12
Any C-
-normal (C-
-normal) Fréchet space is epi-
-normal (epi-
-normal).
Proof
Let
be any C-
-normal (C-
-normal) Fréchet space. Let
be
-normal (
-normal) and
be a bijective function. Since
is Fréchet,
is continuous (see Theorem 1.23). Define
. Obviously,
is a topology on
coarser than
such that
is continuous. Also
is open, since if we take
, then
where
. Thus
which gives that
is open. Therefore
is a homeomorphism. Thus
is
-normal (
-normal). Hence
is epi-
-normal (epi-
-normal).
A topological space
is called lower compact (Kalantan et al., 2019) if there exists a coarser topology
on
such that
is
-compact.
Theorem 2.13
Any lower compact space is C-
-normal (C-
-normal).
Proof
Let
is lower compact, then
is
-compact, hence normal and the identity function
is a continuous and bijective. If we take
any compact subspace of
, then
is a homeomorphism by (Engelking, 1977);3.1.13].
In general, the converse of Theorem 2.13. is not true, for example consider a countable complement topology on an uncountable set, it is C-
-normal (C-
-normal) since it is F-compact, but it is not lower compact because it is not
.
Theorem 2.14
If
is C-
-normal compact Fréchet space and the witness of the C-
-normality is
, then
is lower compact.
Proof
Pick
-normal space
and a bijective function
such that
is a homeomorphism for any compact subspace
. Since
is Fréchet, then
is continuous. Hence
is compact. Since
is
-normal space, then by Lemma 1.11. it is Hausdorff. Hence
is
compact. Define a topology
on
as follows
Then
is coarser than
and
is a bijection continuous function. Let any
, then
is of the form
for some
. Hence
. Thus
is open. Hence
is a homeomorphism. So
is
compact. Therefore
is lower compact.
Theorem 2.15
If
is C-
-normal compact Fréchet space and the witness of the C-
-normality is
, then
is lower compact.