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Numerical solution for Fredholm–Volterra integral equation of the second kind by using collocation and Galerkin methods

Department of Mathematics, Girls College of Education, King Abdul Aziz University, Jeddah, Saudi Arabia
Department of Mathematics, Girls College of Education, UAU, Makkah, Saudi Arabia

*Corresponding author FALHENDI@kau.edu.sa (F.A. Hendi),

Disclaimer:
This article was originally published by Elsevier and was migrated to Scientific Scholar after the change of Publisher.

Abstract

The Fredholm–Volterra integral equation of the second kind with continuous kernels with respect to position and time, is solved numerically, using the Collocation and Galerkin methods. Also the error, in each case, is estimated.

Keywords

45E10
65R10
Integral equation
Continuous kernel
Collocation method
Galerkin method
PubMed
1

1 Introduction

Many problems of mathematical physics, engineering and contact problems in the theory of elasticity lead to integral equations. The following references Muskhelishvili et al. (1953), Green (1969), Atkinson et al. (1976) and Delves and Mohamed (1985), contain many different methods to solve the integral equations analytically. At the same time the numerical methods take an important place in solving the integral equations numerically. The references Linz et al. (1985), Kanwal et al. (1996), Atkinson et al. (1997) and Abdou and Mohamed (2002) contain many different methods for solving the integral equations numerically. The discussion of the Fredholm–Volterra integral equations numerically and analytically can be found in the works of Abdou and co-workers, see (Schiavane and Constanda, 2002; Abdou et al., 2003; Abdou and Salama, 2004), when the Fredholm integral term is considered in position and Volterra integral term in time. In all work of Abdou in Fredholm–Volterra integral equation when the kernel of position is continuous have not been solved.

Therefore, in this paper, we consider the Fredholm–Volterra integral equations of the second kind with continuous kernels with respect to position and time. The existence and uniqueness of the solution, under certain conditions, will be proved in the space L2[a,b]×C[0,T],0tT .

A numerical method is used to represent the Fredholm–Volterra equation in the form of a linear system of Fredholm integral equations where the existence and uniqueness of the system are discussed. Also we used the Collocation and Galerkin methods to obtain a linear system of algebraic equations, which is also solved numerically. Moreover the error estimate, in each case, is calculating.

2

2 The existence and uniqueness of the solution

Consider the Fredholm–Volterra integral equation

(2.1)
μϕ(x,t)-λabk(x,y)ϕ(y,t)dy-λ0tF(t,τ)ϕ(x,τ)dτ=f(x,t) where k(x, y) and F(t, τ) are continuous functions which represent the kernel of Fredholm and Volterra integral terms, respectively. The known function f(x,t) is called the free term of the integral equation, while ϕ(x,t) is unknown and called the potential function. Here the Fredholm is considered in position, while Volterra in time. The constant μ defines the kind of integral equation while the constant λ, may be complex, has a physical meaning.

In order to guarantee the existence of a unique solution of (2.1). We assume the following:

  1. The kernel of position satisfies |k(x,y)|N1 for all, ax,yb, where N1 is a constant.

  2. The positive continuous function F(t,τ)C([0,T]×[0,T]) for all 0t,τT and satisfies |F(t,τ)|N2 where N2 is a constant.

  3. The given function and its norm is defined as: f(x,t)L2[a,b]×C[0,T] , f(x,t)=max0tT0tab{f2(x,τ)}12dxdτ=N3

    where N3 is a constant.

  4. The unknown function ϕ(x,t) satisfy the Lipschitz condition with respect toposition |ϕ(x1,t)-ϕ(x2,t)|A(t)|x1-x2| and Hölder condition with respect to time |ϕ(x,t1)-ϕ(x,t2)|B(x)|t1-t2|α,0α1 , and its norm is defined as ϕ(x,t)=max0tT0tab{ϕ2(x,τ)}12dxdτ=N4

3

3 The system of Fredholm integral equations

For representing (2.1) as a system of Fredholm integral equations we use the following numerical method, see Delves and Mohamed (1985) and Atkinson et al. (1997).

Divide the interval [0, T] as 0=t0<t1<<tk<<tN=T,i.e.t=tk,k=0,1,2,,N.

Then, using the quadrature formula, Te Volterra term in (2.1) becomes

(3.1)
0tkϕ(x,τ)F(tk,τ)dτ=j=0kujF(tk,tj)ϕ(x,tj)+O(ip˜+1),(k0,p˜>0) where k=max0jkhj , hj=tj+1-tj

The values of k and the constant p˜ depend on the number of derivatives of F(t,τ) , for all τ [0, T], w.r.t. t, and u0=12h0,uk=12hk,ui=hi,(i0,k) .

Using (3.1) in (2.1) after letting t=tk,k=1,2,,N, We have

(3.2)
μϕ(x,tk)=f(x,tk)+λabk(x,y)ϕ(y,tk)dy+λj=0kujF(ti,tj)ϕ(x,tk) or,
(3.3)
μϕk(x)=fk(x)+λabk(x,y)ϕk(y)dy+λj=0kujFk,jϕj(x)ϕk(x)=ϕ(x,tk),fk(x)=f(x,tk),Fk,j=F(tk,tj),
the formula (3.3) become
(3.4)
μnϕn(x)=Gn(x)+λabk(x,y)ϕn(y)dy
where μn=μ-λunFn,n ; λn=λunFn,n , Gn(x)=fn(x)+λj=0n-1ujFn,jϕj(x),n=0,1,,N

The formula (3.4) represents a linear system of Fredholm integral equations of the second kind, where λunFn,nμ .

Now, we will solve the linear system (3.4) using the Collocation method and Galerkin method.

3.1

3.1 Collocation method

Collocation method is based on approximating the solution ϕ (x, t) by a partial sum:

(3.5)
S(x,ti)=k=1Nck(ti)ψk(x) of N linearly independent functions ψ1(x), ψ2(x), …, ψN(x) on the interval (a,b). Therefore we have
(3.6)
μSi(x)-λabk(x,y)Si(y)dyf(x,ti)+λj=0i-1wjFi,jSj(x)+ɛ(x,c1(t),c2(t),..,cN(t)+R(ip+1)

Of course, if the approximate solution (3.5) is to be substituted into (3.4) for ϕ(x,t) , there will be an error ɛ(x,c1(t),c2(t),,cN(t)) . This error depends on x, t and the way for which the coefficients c1(t),c2(t),,cN(t) are chosen in the formula (3.6). Let t=ti,i-0,1,2,,N . Then using the quadrature formula, we have

(3.7)
μiSi(xm)-λabk(xm,y)Si(y)dyf(xm,ti)+λj=0i-1wjFi,jSj(xm),i,m=0,1,2,,N

For determining the coefficients c1(ti),c2(ti),,cN(ti) of the approximate solution SN(xN) , from (3.5), in terms of the given N linearly independent functions ψ1(x), ψ2(x), …, ψN(x), perform the integration, then substitute x = x1, x2, …, xN for which the error ɛ(x,c1(t),c2(t),,cN(t)) vanishes.

Substituting from (3.5) in (3.6), we get:

(3.8)
μik=1Nck(ti)ψk(xm)-λk=1Nck(ti)abk(xm,y)ψk(y)dy=fmi+λj=0i-1k=1NwjFi,jck(tj)ψk(xm)

3.2

3.2 Galerkin method

This method establishes the N conditions necessary for the determination of the N coefficients in Eq. (3.5):

By making the error ɛ(x,c1(t),c2(t),,cN(t)) in (3.6) orthogonal to N given linearly independent functions ψ1(x),ψ2(x),,ψN(x) on the interval (a, b), i.e.

(3.9)
abψj(x)ɛ(x,c1(t),c2(t),,cN(t))dx=0

Then from (3.6), we have

(3.10)
abψj(x)[μiSi(xm)-f(xm,y)-λabk(xm,y)Si(y)dy-λj=0i-1wjFi,jSj(x)-R(ip+1)]dx=0

Eq. (3.10) can be written in the form:

(3.11)
abψj(x)[μiSi(xm)-λab[k(xm,y)Si(y)dy-λj=0i-1wjFi,jSj(xm)-R(ip+1)]dx=abψj(x).f(xm,ti)dx(i,m=0,1,,N), where R(ip+1) is the error from dividing the time and i=max0jihj,hj=tj+1-tj . The values of i and the constant p depend on the derivatives of F(t, τ), for all τ[0,T] , with respect to t. Substituting from (3.5) into (3.11) we get
(3.12)
abψj(x)[μik=1Nck(ti)ψk(xm)-λabk(xm,y)·k=1Nck(ti)ψk(y)dy-λj=0i-1wjFi,jk=1Nck(tj)ψk(xm)]dx=abψj.(x)f(xm,ti)dx

4

4 Examples

Example 4.1

Consider the integral equation: ϕ(x,t)=f(x,t)+λ0tτ2ϕ(x,τ)dτ+λabex+yϕ(y,t)dy where the exact solution ϕ(x,t)=t2ex .

4.1

4.1 Using collocation method

In Eq. (4.1) we shall take N = 2, a = 0, b = 1, f(x,t)=32t2ex-15ext5-12t2exe2

Let the approximate solution has the form of Eq. (3.5), the three independent functions are ψ1(x)=1,ψ2(x)=x,ψ3(x)=x2 . Substituting these values in Eq. (3.8), then solving the equations formulas when x = 0, 0.5, 1.0, in this case R = 0. We get:

(4.1)
c1(t0)=0,c2(t0)=0,c3(t0)=0.c1(t1)=0.0005130967957,c2(t1)=0.000432839493,c3(t1)=0.000415594769.
(4.2)
c1(t2)=0.002104378751,c2(t2)=0.001731361786,c3(t2)=0.001662382707.

So, the solution, for t  [0, 0.03], takes the form (see Table 1):

(4.3)
S(x,t0)=0S(x,t1)=0.0005130967957+0.000432839493x-0.000415594769x2S(x,t2)=0.002104378751+0.001731361786x+0.001662382707x2
Table 1 Values of the error EC,EG using collocation and Galerkin methods.
x ϕ(x,t) EC EG
t = 0
0 0 0 0
0.5 0 0 0
1.00 0 0 0
t = 0.01500000000
0 0.000225 0.0002880967957 0.00029449274
0.5 0.0003709622860 0.0004624529484 0.0004622507140
1.00 0.0006116134113 0.0007499176467 0.0007425012987
t = 0.030000000
0 0.0009 0.001204378714 0.00122991170
0.5 0.001483849144 0.001901806122 0.001900946656
1.00 0.002446453645 0.003051669518 0.003021953955

4.2

4.2 Using Galerkin method

As in collocation method, using (3.9) in (3.12), Choose three independent functions ψ1(x)=1,ψ2(x)=x,ψ3(x)=x2 and three points x = 0, 0.5, 1.00, when we assume t  [0, 0.03], then we have:

(4.4)
c1(t0)=0,c2(t0)=0,c3(t0)=0.c1(t1)=0.00051949274,c2(t1)=0.00042025907,c3(t1)=0.00041436290.c1(t2)=0.00212991168,c2(t2)=0.0016810402,c3(t2)=0.0016574556.
(4.5)
S(x,t0)=0,S(x,t1)=0.00051949274+0.00042025907x+0.00041436290x2,S(x,t2)=0.00212991168+0.0016810402x+0.0016574556x2.

So, the solution is taken from:

Example 4.2

Consider the integral equation:

(4.6)
ϕ(x,t)=f(x,t)+λ0ttτϕ(x,τ)dτ+λabe-yϕ(y,t)dy, where the exact solution ϕ(x,t)=te-x .

4.3

4.3 Using collocation method

In Eq. (4.6) we shall take N = 2, a = 0, b = 1, f(x,t)=-0.00432t+e-xt-0.333e-xt4.

Let the approximate solution in the form of Eq. (3.5), then choose three independent functions ψ1(x)=1,ψ2(x)=x,ψ3(x)=x2 . Substituting these values in Eq. (3.8), then solving the equations formulas, when x = 0, 0.5, 1.00, in this case R = 0, we get:

(4.7)
c1(t0)=0,c2(t0)=0,c3(t0)=0.c1(t1)=0.008541939634,c2(t1)=-.01412633660,c3(t1)=0.004644538564.c1(t2)=0.01708389624,c2(t2)=-0.02825268914,c3(t2)=0.009289082405

So, the solution, for t  [0, 0.03] takes the form:

(4.8)
S(x,t0)=0,S(x,t1)=0.008541939634-0.01412633660x+0.004644538564x2,S(x,t2)=0.01708389624-0.02825268914x+0.009289082405x2.

4.4

4.4 Using Galerkin method

We choose three independent functions ψ1(x)=1,ψ2(x)=x,ψ3(x)=x2 and three points x = 0, 0.5, 1.00, when we assume t  [0, 0.03], we have:

(4.9)
c1(t0)=0,c2(t0)=0,c3(t0)=0.c1(t1)=0.008459192683,c2(t1)=-0.01395821152,c3(t1)=0.00463077286.c1(t2)=0.01691840427,c2(t2)=-0.02791644232,c3(t2)=0.00926155092. So, the solution is taken the form (see Table 2):
(4.10)
S(x,t0)=0,S(x,t1)=0.008459192683-0.01395821152x+0.00463077286x2,S(x,t2)=0.01691840427-0.02791644232x+0.00926155092x2.
Table 2 Values of the error EC,EG using collocation and Galerkin methods.
x ϕ(x,t) EC EG
t = 0
0 0 0 0
0.5 0 0 0
1.00 0 0 0
t = 0.01500000000
0 0.015 0.006458060366 0.006540807317
0.5 0.009097959896 0.006458053921 0.006460179758
1.00 0.005518191618 0.006458050020 0.006386437595
t = 0.030000000
0 0.03 0.01291610376 0.01308159573
0.5 0.01819591979 0.01291609752 0.01292034895
1.00 0.01103638324 0.01291609374 0.01277287037

Acknowledgements

The authors would like to thank professor M.A. Abdou (University of Alexandria, Egypt) for his helpful remarks and suggestions.

References

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