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ABUNDANCE ESTIMATION IN AN ARID ENVIRONMENT
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ABUNDANCE ESTIMATION IN AN ARID ENVIRONMENT
Case Study
Editorial
Invited review
Letter to the Editor
Original Article
REVIEW
Review Article
SHORT COMMUNICATION
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SHORT COMMUNICATION
26 (
2
); 159-160
doi:
10.1016/j.jksus.2014.01.002

A note on “Jacobi elliptic function solutions for the modified Korteweg–de Vries equation”

Zhijiang College, Zhejiang University of Technology, Post-Office Box: 6044, Zhijiang Road 182, Hangzhou 310024, China

*Tel.: +86 571 87317741 mathlhz@163.com (Hong-Zhun Liu)

Disclaimer:
This article was originally published by Elsevier and was migrated to Scientific Scholar after the change of Publisher.

Peer review under responsibility of King Saud University.

Available online 23 January 2014

Abstract

The recently published paper “Jacobi elliptic function solutions for the modified Korteweg–de Vries equation” [J. King Saud Univ. Sci. 25 (2013) 271–274] is analyzed. We show that these Jacobi elliptic function solutions obtained by the authors do not satisfy the original modified Korteweg–de Vries equation.

Keywords

Modified Korteweg–de Vries equation
Traveling wave solution
Tanh method
Common error

Recently, Wang and Xiang (2013) studied the modified Korteweg–de Vries (mKdV) equation in the form

(1)
λ u t - μ u 2 u x + wu xxx = 0 , where λ , μ and w are constant parameters. They sought solutions by taking the traveling waves into account
(2)
u ( x , t ) = u ( ξ ) , ξ = α x + kt .

As a result they transform (1) to an ordinary differential equation (ODE) in the form

(3)
c + k λ u - μ α 3 u 3 + w α 3 u ξ ξ = 0 , where c is an integral constant. They expressed u as
(4)
u = u 0 + pu 1 + p 2 u 2 ,
where p is a small parameter, and u 0 , u 1 and u 2 are ansatz functions to be determined.

Substituting (4) into (3), we have

(5)
c + k λ u 0 - μ α 3 u 0 3 + w α 3 u 0 ξ ξ + p · ( k λ u 1 - μ α u 0 2 u 1 + w α 3 u 1 ξ ξ ) + p 2 · ( k λ u 2 - μ α u 0 2 u 2 - μ α u 0 u 1 2 + w α 3 u 2 ξ ξ ) - p 3 · 2 μ α u 0 u 1 u 2 + μ α 3 u 1 3 - p 4 · μ α u 2 ( u 0 u 2 + u 1 2 ) - p 5 · μ α u 1 u 2 2 - p 6 · μ α 3 u 2 3 = 0 .

Since (4) is a solution of (3), (5) must hold for all values of p. Then each coefficient of p must vanish independently. Thus

(6)
c + k λ u 0 - μ α 3 u 0 3 + w α 3 u 0 ξ ξ = 0 ,
(7)
k λ u 1 - μ α u 0 2 u 1 + w α 3 u 1 ξ ξ = 0 ,
(8)
k λ u 2 - μ α u 0 2 u 2 - μ α u 0 u 1 2 + w α 3 u 2 ξ ξ = 0 ,
(9)
2 μ α u 0 u 1 u 2 + μ α 3 u 1 3 = 0 ,
(10)
μ α u 2 ( u 0 u 2 + u 1 2 ) = 0 , μ α u 1 u 2 2 = 0 , μ α 3 u 2 3 = 0 .

The solution of (9) and (10) is u 2 = u 1 = 0 . In this case, the left hand side of (7) and (8) vanishes. So u = u 0 , and both of u and u 0 satisfy the same ordinary differential equation, which means nothing can be obtained from above approach.

It is a pity that Wang and Xiang (2013) obtained u 0 , u 1 and u 2 through solving only three equations, namely (6)–(8) and neglected the rest of the equations. Then they claimed “The Jacobi elliptic function solutions, the trigonometric solutions and hyperbolic solutions are obtained”. It is not difficult to find that these solutions, namely (22)–(24) in their paper, are not admitted by the original mKdV equation.

In particular, the solution (24) in their paper, namely,

(11)
u ( x , t ) = a 1 tanh ξ + pg 0 sech 2 ξ + p 2 b 1 tanh ξ + p 2 b 3 tanh 3 ξ can also be checked by the tanh method (see, for example, Malfliet (2004)) easily. In fact, by replacing sech 2 ξ with 1 - tanh 2 ξ , the solution (11) is transformed into the following
(12)
u ( x , t ) = pg 0 + ( a 1 + p 2 b 1 ) Y - pg 0 Y 2 + p 2 b 3 Y 3 ,
where Y = tanh ξ is an introduced variable.

The tanh method proposes the following solution admitted by (3)

(13)
u = a 0 + a 1 Y + + a N Y N = n = 0 n = N a n Y n , where N is a positive integer to be determined. Balancing the highest order linear term u ξ ξ in (3) with the highest order nonlinear term u 3 gives N + 2 = 3 N , so N = 1 , which means the proposed solution will be
(14)
u = a 0 + a 1 Y .
However, the solution (12) indicates N = 3 . This is a contradiction.

Finally, we notice that c = 0 in the results of Wang and Xiang (2013). And in this case, (3) can be changed to an ODE of degree four in the form

(15)
u ξ 2 = h 0 + h 2 u 2 + h 4 u 4 , where h 0 is an arbitrary constant, and h 2 and h 4 are certain constants. Many exact solutions of (15) have been presented and have played an important role in recently published papers, for example, Shang (2010); Alofi and Abdelkawy (2012); Ebaid and Aly (2012); Li et al. (2012); Ma et al. (2012); and Malik et al. (2012b,a). And its general solutions can be found in some literature, for example, Whittaker and Watson (1996) and Liu et al. (2014). Consequently, we can obtain general solutions of (3) in the case of c = 0 directly. Due to limited space, here we omit its discussion.
Remark

It is worth to mention that if we regard the results obtained by Wang and Xiang (2013) as approximate solutions (in contrast to exact solutions), we can find that the derivations and results are correct. However, in this sense, these authors should express them in a proper way, and relevant calculated precisions for these solutions should be discussed as well, for example, see Holmes (2013).

In summary, solutions obtained by these authors do not satisfy the original mKdV equation. We have to point out that similar concerns are discussed in some other published papers as well (see, for examples, Kudryashov (2009) and Kudryashov and Shilnikov (2012)). We believe that our work will help people have a good understanding of the results obtained by Wang and Xiang (2013).

Acknowledgment

Many thanks are due to the helpful comments and suggestions from the anonymous referees and the editors.

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